Answer:
Mass of Methyl alcohol (or methanol) = 0.1403g
Explanation:
<u>Step 1:</u> Given data
Mass of Sample: ms = 0.220 g
Mass of CO2: m0 = 0.345 g
Mass of CH3OH = m1
Mass of C2H5OH = m2
Molar mass CO2 = 44.01 g/mole
Molar mass CH3OH = 32 g/mole
Molar mass C2H5OH 46.07 g/mole
<u>Step 2: </u>Tjhe balanced equation
2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
C2H5OH + 3 O2 =2 CO2 + 3 H2O
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2 CH3OH + C2H5OH + 6 O2 = 4 CO2 + 7 H2O
<u>Step 3:</u> Calculate mass
In the balanced equation we notice that , the amount of CO2 is related to the amount of the alcohols: Moles CO2 = 4
mass of CO2 = Molar mass CO2((mass CH3OH/ Molar mass CH3OH)+(mass C2H5OH/Molar mass C2H5OH))
mass of CO2 = 44.01 ((mass CH3OH/ 32.04) + (mass C2H5OH/ 46.07)
The sample has a mass of 0.220 g = mass CH3OH + mass C2H5OH
mass C2H5OH = 0.220G - mass CH3OH
This we will insert in the equation, so we will only have 1 unknown mass
0.345g = 44.01((m1/32.04) + (2(0.220-m1)/M2) )
<=> m1 = ((mCO2/44.01)-(2*0.22/46.07))÷((1/32.04)-(2/46.07))
Thus: m1 = ((0.345/44.01)-(2*0.220/46.07))÷((1/32.04)-(2/46.07))
Thus m1 = 0.1403 g = Mass of CH3OH
Since m2=(ms-m1).
m2 = 0.220-0.1403 = 0.0797 g = Mass of C2H5OH
Mass of methyl alcohol (Methanol) = 0.1403g
Mass of ethyl alcohol (Ethanol) = 0.0797g.
