Answer: Mass of hydrogen produced is 0.0376 g.
Explanation:
The reaction equation will be as follows.

Now, formula for total pressure will be as follows.

Hence, 
= 755 mm Hg - 42.23 mm Hg
= 712.77 mm Hg

= 0.937 atm
Now, we will calculate the moles of
as follows.


n =
mol
= 0.0187 mol
Therefore, mass of
will be calculated as follows.

= 0.0376 g
Thus, we can conclude that mass of hydrogen produced is 0.0376 g.
Answer:
Part A: Hexacyanoferrate (III)
Part B: DiammintetraaquoCupperate (II)
Part C: Dichlorobis(ethylenediamine) Chromate (II)
Part D: Triaquocarbonylnickel (II) Sulphate
Part E: Potassium Dicarbonatedifluoroplatinate (II)
Explanation:
For naming the complex ions there is a specific rule
Nomenclature of the complex ions are as follow
- write a correct formulae
- Indicate the oxidation number of metal in the complex
- The oxidation number should write in the roman numeral in perenthasis after metal name
- Ligand named before the metal ion
- Ligan can be named in following order
* 1st negative, 2nd neutral, 3rd positive
* If there are more than 2 same charged ligand the write in
alphabetical order.
- Write prefix i.e di, tri, tetra for multiple monodentate ligands
- Anions name end at ido the replace the final name.
- Neutral ligands named as their usual name, but there are some exceptions such as
NH3 named as ammine
H2O names aqua or aquo
CO named ascarbonyl
NO named as nitrosyl
- If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
- The name of full complex will end with cation or anion with separate word.
Keeping the rules in mind the complexes named as following.
_________________________
Part A:
[Fe(CN)₆]³⁻
Name of the Complex : Hexacyanoferrate (III)
___________________
Part B:
[Cu(NH₃)₂(H₂O)₄]²⁺
Name of the Complex : DiammintetraaquoCupperate (II)
_______________________
Part C
CrCl₂(en)₂
Name of the Complex : Dichlorobis(ethylenediamine) Chromate (II)
________________________
Part C
[Ni(H₂O)₃(CO)]SO₄
Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate
______________________
Part E
K₄[Pt(CO₃)₂F₂]
Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)
Its a heterogeneous mixture
The parts are not uniformly mixed
pH of solution = 9.661
<h3>Further explanation
</h3>
pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.
pOH=-log[OH⁻]
![\tt pOH=-log[4.583\times 10^{-5}]\\\\pOH=5-log~4.583=4.339](https://tex.z-dn.net/?f=%5Ctt%20pOH%3D-log%5B4.583%5Ctimes%2010%5E%7B-5%7D%5D%5C%5C%5C%5CpOH%3D5-log~4.583%3D4.339)
pH+pOH=pKw
