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Mazyrski [523]
3 years ago
6

Help me plzz it’s for

Chemistry
1 answer:
Rudik [331]3 years ago
5 0
What is it ? I can’t see
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find the mass of h2 produced Binary compounds of alkali metals and hydrogen react with water to produce H2(g). The H2H2 from the
scZoUnD [109]

Answer: Mass of hydrogen produced is 0.0376 g.

Explanation:

The reaction equation will be as follows.

NaH(aq) + H_{2}O(l) \rightarrow H_{2}(g) + NaOH(aq)

Now, formula for total pressure will be as follows.

  P_{total} = P_{H_{2}} + P_{H_{2}O}

Hence,    P_{H_{2}} = P_{total} - P_{H_{2}O}

                            = 755 mm Hg - 42.23 mm Hg

                            = 712.77 mm Hg

P_{H_{2}} = \frac{712.77 \times 1 atm}{760 mm Hg}

             = 0.937 atm

Now, we will calculate the moles of H_{2} as follows.

   P_{H_{2}}V = nRT

   0.937 atm \times 0.505 L = n \times 0.0821 \times 308.15 K

      n = \frac{0.473}{25.29} mol

         = 0.0187 mol

Therefore, mass of H_{2} will be calculated as follows.

        m_{H_{2}} = \frac{0.0187 mol \times 2.0158 g}{1 mol}

                   = 0.0376 g

Thus, we can conclude that mass of hydrogen produced is 0.0376 g.

7 0
3 years ago
Part A Name the complex ion [Fe(CN)6]^3- . The oxidation number of iron is +3. Part B Name the complex ion [Cu(NH3)2(H2O)4]^2+ .
zvonat [6]

Answer:

Part A: Hexacyanoferrate (III)

Part B: DiammintetraaquoCupperate (II)

Part C: Dichlorobis(ethylenediamine) Chromate (II)

Part D: Triaquocarbonylnickel (II) Sulphate

Part E: Potassium Dicarbonatedifluoroplatinate (II)

Explanation:

For naming the complex ions there is a specific rule

Nomenclature of the complex ions are as follow

  • write a correct formulae
  • Indicate the oxidation number of metal in the complex
  • The oxidation number should write in the roman numeral in perenthasis after metal name
  • Ligand named before the metal ion
  • Ligan can be named in following order

                  * 1st negative,  2nd neutral, 3rd positive

                  * If there are more than 2 same charged ligand the write in                      

                    alphabetical order.

  • Write prefix i.e di, tri, tetra for multiple monodentate ligands
  • Anions name end at ido the replace the final name.
  • Neutral ligands named as their usual name, but there are some exceptions such as

                                      NH3 named as ammine

                                      H2O names aqua or aquo

                                     CO named ascarbonyl

                                      NO named as nitrosyl

  • If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
  • The name of full complex will end with cation or anion with separate word.  

Keeping the rules in mind the complexes named as following.

_________________________

Part A:

[Fe(CN)₆]³⁻

Name of the Complex : Hexacyanoferrate (III)  

___________________

Part B:

[Cu(NH₃)₂(H₂O)₄]²⁺

Name of the Complex : DiammintetraaquoCupperate (II)

_______________________

Part C

CrCl₂(en)₂

Name of the Complex :  Dichlorobis(ethylenediamine) Chromate (II)

________________________

Part C

[Ni(H₂O)₃(CO)]SO₄

Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate

______________________

Part E

K₄[Pt(CO₃)₂F₂]

Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)

5 0
3 years ago
The mixture you separated was a mixture of iron filings, sand, and salt. Based on your understanding of matter, is this mixture
Anarel [89]
Its a heterogeneous mixture

The parts are not uniformly mixed
5 0
3 years ago
Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)​
Sergeu [11.5K]

pH of solution = 9.661

<h3>Further explanation </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

pOH=-log[OH⁻]

\tt pOH=-log[4.583\times 10^{-5}]\\\\pOH=5-log~4.583=4.339

pH+pOH=pKw

\tt pH=14-4.339\\\\pH=9.661

8 0
3 years ago
IM ON A TIME LIMIT ANSWER FAST ILL GIVE 20 POINTS AND A BRAINEST ANSWERHow will a short-term environmental change most likely af
gtnhenbr [62]

Answer:

first and 4th

Explanation:

4 0
3 years ago
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