Calcium carbonate has the formula: CaCO3
From the periodic table:
mass of calcium = 40 grams
mass of carbon = 12 grams
mass of oxygen = 16 grams
Therefore,
molar mass of CaCO3 = 40 + 12 + 3(16) = 100 grams
molar mass of carbonate = 12 + 3(16) = 60 grams
One mole of calcium carbonate contains one mole of carbonate. Therefore, 100 grams of CaCO3 contains 60 grams of CO3.
If the 0.5376 grams of the unknown substance is CaCO3, then the amount of carbonate will be:
amount of carbonate = (0.5376*60) / 100 = 0.32256 grams
Based on the above calculations, the sample is not CaCO3
Answer:
64799.4 J
Explanation:
The following data were obtained from the question:
Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g
Specific heat capacity (C) = 0.9211 J/g°C
Initial temperature (T1) = 23°C
Final temperature (T2) = 90°C
Change in temperature (ΔT) = T2 – T1 =
90°C – 23°C = 67°C
Heat required (Q) =....?
The heat required to increase the temperature of the kettle can b obtain as follow:
Q = MCΔT
Q = 1050 x 0.9211 x 67
Q = 64799.4 J
Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.
Answer:
C. results when an alkaline-earth metal loses one of its outermost electrons
Explanation:
An ion can be said to result when an alkaline - earth metal loses one of its outermost electrons.
Ions are charged substances that takes part in chemical reaction.
- An an atom is neutral substance that is a component of an element.
- An ion is charged substance.
- In an ion, the number protons and electrons are unbalanced.
- The number of protons in an atom are the positively charged particles.
- The number of electrons are the negatively charged particles.
When there is an inequality between the number of protons and electrons within an atom, an ion forms.
Answer:

Explanation:
Hello,
In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

Now, the total volume is:

Which is equal to:

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

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