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k0ka [10]
2 years ago
6

PLEASE HRLP IM BEGING TIMED: science

Chemistry
1 answer:
Alex17521 [72]2 years ago
7 0

Answer: If two positive charges interact, their forces are directed against each other. The two charges repel each other.

Explanation: The same occurs with two negative charges, because their respective forces also act in opposite directions.) The electric field and resulting forces produced by two electrical charges of the same polarity.

Good luck luv.

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If you had a sample containing 55 alpha particles, how many protons would be present in that sample? Show all necessary work.
arlik [135]
An alpha particle is a helium nucleus without the electrons - 2 neutrons and 2 protons.

So, all you would have to do is 2 x 55, which equals 110.

8 0
3 years ago
Which is an example of a bioresource used to build a home?
lutik1710 [3]
The answer should be A.
Hope this helps :-)
4 0
2 years ago
What is 2n^2 rule ( of science)​
lozanna [386]

2n² rule:

This rule is used to determine number of electrons in particular shell.

n=1 means K shell

n=2 means L shell

n=3 means M shell

n=4means N shell

The first K shell can hold upto 2 electrons, L shell can hold up to 8, third M shell can hold up to 18and the fourth N shell can hold upto 32 electrons. This rule of arrangement of electrons according to the shell is known 2n2 rule where n means number of shell.

For example: There is one proton in the nucleus of hydrogen atom, which moves in K shell path. It has no neutron.

3 0
3 years ago
A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40
Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = 40 hr/week\times 8 week = 320 hours

The concentration of xylene in the workplace =40 \mu g/m^3

The worker is inhaling air at a rate of 0.9 m^3/hr.

Amount xylene inhaled by worker in an hour :

= 40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr

Amount xylene inhaled by worker in 320 hours:

36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

\frac{24}{320}\times 11.520 mg=0.864 mg

Assuming 70 kg body mass, the chronic daily intake of xylene :

\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0
2 years ago
Match the prefix with the power of ten it represents.
Sunny_sXe [5.5K]

kilo 103 is the correct answer so it would mostly be 2

6 0
3 years ago
Read 2 more answers
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