I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
A
Step-by-step explanation:
Points of origin are (-3,0) and (0,1). Now we determine if it is a positive slope, it is as it goes up not down. It goes up 1 unit and over to the right 3 units, making the slope 1/3.
Answer:
The answer is -2 1/6 because it the only on that works.
Step-by-step explanation:
yeah no
Answer:
c
Step-by-step explanation:
50×1=50
50×3=150
50×4=200
50×5=250
You have to find the least common multiple of the denominators (bottom), and when you do that, you multiply the numerator(top) by the same number. You then add or subtract the numerators. You leave the denominators as they are. Simplify if needed.
