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3 years ago

Diego's club earns money for charity when members of the club perform community service after school,

Mathematics

1 answer:

likoan [24]3 years ago

6 0

Answer: Yes, because the input value can be a number between 0 and 12.

Step-by-step explanation:

Hi, to answer this question we have to write an function that represents the situation.

Since each student who does community service, the club earns $5

E(s) = 5 s

Where:

<em>E= total amount earned</em>
<em>n = number of students that do community services (input value)</em>

Yes, because the input value n is the number of students in the club that do comunity services. Since the number of students in the club is 12, the input value can be a number between 0 and 12.

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In San Diego the average cost of gas is $4.15 per gallon. If a car has a fuel efficiency of 24 miles per gallon and the owner of

KIM [24]

Answer:

$25.94

Step-by-step explanation:

150 ÷ 24 = 6.25

6.25 × 4.15 = 25.9375

25.94

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3 years ago

A spherical ball has a diameter of 12 inches. The ball has a slow leak in which air escapes at the rate of 4.5 cubic inches per

stellarik [79]

Answer:

Step-by-step explanation:

It would be 54 because 12*4.5 = 54.

6 0

3 years ago

Someone please help??

ivolga24 [154]

(B) is your answer for sure is what i would say

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3 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

3 years ago

Help is needed! Desperate

Bogdan [553]

Sorry I don't know that question.

5 0

3 years ago

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