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3 years ago

Diego's club earns money for charity when members of the club perform community service after school,

Mathematics

1 answer:

likoan [24]3 years ago

6 0

Answer: Yes, because the input value can be a number between 0 and 12.

Step-by-step explanation:

Hi, to answer this question we have to write an function that represents the situation.

Since each student who does community service, the club earns $5

E(s) = 5 s

Where:

E= total amount earned
n = number of students that do community services (input value)

Yes, because the input value n is the number of students in the club that do comunity services. Since the number of students in the club is 12, the input value can be a number between 0 and 12.

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Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance

zzz [600]

Answer:

$\frac{\Delta v}{v}=0.426$

Step-by-step explanation:

you have that the average sped is given by the following formula:

$v(x,t)=\frac{x}{t}$

The uncertainty formula for a division is given by:

$\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}$ (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

$\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426$

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0

3 years ago

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

$\dfrac{A}{A'}=\dfrac{P^2}{P'^2}$

We are given:

A=72 dm^2 , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. $\dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}$

on taking square root on both the side we get:

$\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'$

Now putting the value of P in equation (1) we obtain:

$\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272$

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0

3 years ago

What's -8+9w+(-23) ????

zvonat [6]

First simplify
-8+9w-23
Then Group simliar terms
(-8-23)+9w
After simplify
-31 +9w

8 0

3 years ago

What is the domain of the relation graphed below?

vova2212 [387]

Answer:

Step-by-step explanation:

6 0

2 years ago

Determine if direct variation x-2y=0

Fofino [41]

Answer:

x-2y=0 is a direct variation

Step-by-step explanation:

Direct variation is of the form

y= kx

Can we get the equation in that form

x-2y =0

Add 2y to each side

x-2y+2y =0_2y

x=2y

Divide each side by 2

x/2 = 2y/2

1/2x =y

Flip the sides

y = 1/2x

This is of the form y= kx where k = 1/2

x-2y=0 is a direct variation

3 0

3 years ago