Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
Step-by-step explanation:
- First, the radical needs to be alone on one side of the equation, if there is - 4, - 3 next to it then you'll have to transfer it to the opposite side like that:
5. (y+7)^0.5 - 4=4
(y+7)^0.5=8......
- Second, you need to square the two sides of the equation :
5.((y+7)^0.5) ^2=8^2
Y+7=64
Y+7-7=64-7
Y=57
Note: if the radical's index is (2) then you'll square the two sides of the equation, but if the index is (3) you'll have to cube the two sides of the equation, "look at the exercises 9,10"
If the frame to hold the picture is 25 5/6 inches height, then the picture to put in it should be the same height: <span>25 5/6 inches
perhaps a little bit smaller for it to fit properly</span>
<u>2/5 x + 1/3 x = 22</u>
First of all, I've been answering so many of these things lately that I'm
getting really tired of 'x'. Let's call the unknown number ' Q ' instead.
<u>2/5 Q + 1/3 Q = 22</u>
Multiply each side by 5 :
2Q + 5/3 Q = 110
Multiply each side by 3 :
6Q + 5Q = 330
Add the like terms on the left side:
11Q = 330
Divide each side by 11 :
<u>Q = 30</u> .
