Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5
thus,
x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2
The answer is option C
Answer:
x<8
Step-by-step explanation:
Had that same question
The vertex is (3,5).
There is no x intercept. Because
has no real solutions.
The y intercept is 14. Because:
Answer:
2
Step-by-step explanation:
Answer:
115.248
Step-by-step explanation:
120−96×[5 ÷ {23 − 3 × (12 − 22 − 16)}]
120−96×[5 ÷ {23 − 3 × (-26)}]
120−96×[5 ÷ {101}]
120−96×[0.0495]
115.248
Just remember PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction
