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3 years ago

Which is a characteristic of a synthesis reaction

Chemistry

2 answers:

V125BC [204]3 years ago

8 0

Answer:option A
Multiple reactants are used to form one product.

Igoryamba3 years ago

6 0

Answer : The correct option is, (A) There is more than one reactant.

Explanation :

Synthesis reaction : Synthesis reaction are those reactions in which more than one reactants react to form a single product or a compound.

The general representation of the synthesis reaction is,

$A+B\rightarrow AB$

In this, A and B are the reactants and AB is the product.

For example : formation of calcium hydroxide from calcium oxide and water.

$CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)$

Hence, the correct answer is, (A)

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How many significant figure does 60600 have?

irga5000 [103]

The answer would be 5. because the last zero is a holding place because the number is in front of the decimal. They other zero counts because they are being sandwiched.

7 0

3 years ago

Read 2 more answers

Calculate the no. of moles in 25gm of calcium phosphate Plz Fast Urgent

madreJ [45]

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

7 0

3 years ago

What mass of each solute is present in 294 g of a solution that contains 4.86% by mass NaCl and 7.54% by mass Na2CO3

Angelina_Jolie [31]

In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams

Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams

7 0

3 years ago

If 60g of rust (Fe2O₁) are made in the reaction below, how many Liters of oxygen must be used?

Aleksandr [31]

Answer:

18.

Explanation:

1) according to the reaction (M(Fe)=56; M(O₂)=32; V₀=22.4):

4Fe+3O₂⇒2Fe₂O₃; - ν(O₂)=0.75*ν(Fe);

2) ν(Fe)=m(Fe)/M(Fe)=60/56≈1.071 [mol];

3) ν(O₂)=0.75*1.071=0.804 [mol];

4) V(O₂)=V₀*ν(O₂); ⇒ V(O₂)=22.4*0.804=18 [lit].

7 0

2 years ago

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the

butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we calculate how many HCl moles reacted, using the given concentration and volume:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We determine how many NaOH moles reacted:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:

5.165 mmol NaOH * $\frac{1mmolH_3PO_4}{3mmolNaOH}$ = 1.722 mmol H₃PO₄

Finally we determine the H₃PO₄ solution concentration:

1.722 mmol / 10.0 mL = 0.172 M

5 0

3 years ago