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kykrilka [37]
3 years ago
10

Each year, the science club puts on a science show for the students in the elementary school. Luis is planning demonstrations to

show properties of metals. For one property, he decides to use a ball of pizza dough and a rolling pin. Which property of metals is Luis most likely going to demonstrate using these materials
Chemistry
2 answers:
Luda [366]3 years ago
7 0

Explanation:

Metals are the elements which contain more number of electrons.

Some properties of metals are as follows.

  • Metals have shiny surface.
  • Metals are malleable, i.e, they can be drawn into thin sheets.
  • Metals are ductile, i.e, they can be drawn into thin wires.
  • Metals have high melting and boiling point.

Thus, when Luis decides to use a ball of pizza dough and a rolling pin then it represents the property of malleability, that is, with the help of rolling pin pizza dough can be drawn into thin sheet.

Harlamova29_29 [7]3 years ago
6 0

Mallebility, I got it right on the unit test.

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Determine the rate law and the value of k for the following reaction using the data provided.
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<u>Answer:</u> The rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

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Rate law expression for the reaction:

\text{Rate}=k[NO]^a[O_2]^b

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b = order with respect to oxygen

  • <u>Expression for rate law for first observation:</u>

8.55\times 10^{-3}=k(0.030)^a(0.0055)^b       ....(1)

  • <u>Expression for rate law for second observation:</u>

1.71\times 10^{-2}=k(0.030)^a(0.0110)^b       ....(2)

  • <u>Expression for rate law for third observation:</u>

3.42\times 10^{-2}=k(0.060)^a(0.0055)^b      ....(3)

Dividing 1 from 2, we get:

\frac{1.71\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.030)^a(0.0110)^b}{(0.030)^a(0.0055)^b}\\\\2=2^b\\b=1

Dividing 1 from 3, we get:

\frac{3.42\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.060)^a(0.0055)^b}{(0.030)^a(0.0055)^b}\\\\2^2=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}

Hence, the rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

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