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suter [353]
3 years ago
9

I need help with this question please Chemistry

Chemistry
1 answer:
ivolga24 [154]3 years ago
5 0
I cannot see it can you make it bigger by any chance dm me on Instagram
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Will mark Brainly us if you help me
ohaa [14]

Answer: ok, its C

Explanation: I used D=26.4* 3 to calculat it

5 0
3 years ago
Calculate the mass, in grams, of each sample. a. 1.1 * 1023 gold atoms b. 2.82 * 1022 helium atoms c. 1.8 * 1023 lead atoms d. 7
Vlada [557]

Answer:blablablablablabla

Explanation:

Blablabla

5 0
3 years ago
30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter
mihalych1998 [28]
First, calculate the number of moles of sodium present with the given mass,

              31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

           mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
                  mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.
                
                 volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
                     volume of H2 = 15.34 L

Answer: 15.34 L
3 0
3 years ago
A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

that is PV=nRT   where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

T(temperature) = 11°c into kelvin =11+273 =284 k

make  p the subject of the formula by  diving both side by V

p =nRT/v


p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



Total  pressure  is therefore = 0.205 atm +0.658 atm +0.539 atm

=1.402 atm

6 0
3 years ago
For the reaction 2A + 4B ----&gt; 2C + 2D, at a particular instant in time, the rate of the reaction is 0.0352 M/s. What is the
viva [34]

Explanation:

The given chemical equation is:

2A + 4B -> 2C + 2D

The rate of the reaction is 0.0352 M/s.

During the course of the reaction, the rate of reactants decreases, and the rate of products increases.

The rate of disappearance of B is shown below:

rate=-\frac{1}{4} \frac{d[B]}{dt}

So, rate of change of B is :

rate of change of B =- rate * 4\\=-0.0352 M/s * 4\\=-0.1408M/s\\\\=-0.141M/s

Option C.

6 0
2 years ago
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