Answer: ok, its C
Explanation: I used D=26.4* 3 to calculat it
First, calculate the number of moles of sodium present with the given mass,
31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium
It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.
mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2
Then, at STP, 1 mol of gas = 22.4 L.
volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L
Answer: 15.34 L
The total pressure = 1.402 atm
<u><em>calculation</em></u>
Total pressure = partial pressure of gas A + partial pressure of gas B + partial pressure of third gas
partial pressure of gas A= 0.205 atm
Partial pressure of gas B =0.658 atm
partial pressure for third gas is calculated using ideal gas equation
that is PV=nRT where,
p(pressure)=? atm
V(volume) = 8.65 L
n(moles)= 0.200 moles
R(gas constant)=0.0821 L.atm/mol.k
T(temperature) = 11°c into kelvin =11+273 =284 k
make p the subject of the formula by diving both side by V
p =nRT/v
p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm
Total pressure is therefore = 0.205 atm +0.658 atm +0.539 atm
=1.402 atm
Explanation:
The given chemical equation is:
The rate of the reaction is 0.0352 M/s.
During the course of the reaction, the rate of reactants decreases, and the rate of products increases.
The rate of disappearance of B is shown below:
![rate=-\frac{1}{4} \frac{d[B]}{dt}](https://tex.z-dn.net/?f=rate%3D-%5Cfrac%7B1%7D%7B4%7D%20%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D)
So, rate of change of B is :
Option C.
