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Reika [66]
3 years ago
6

Can someone explain the steps to solve number two?

Mathematics
1 answer:
Vlada [557]3 years ago
7 0
Ok so first you would create a proportion.
8/x=4/1. Next you cross multiply and divide,
1 • 8÷4=x. Ratios are fractions with the first number being the numerator and the second being the denominator. If you think of it this way, you just find an equivalent fraction. Your answer would be 8:2 because in your proportion x=2.
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What is the range of possible sizes for side x? it is a triangle with one side having 4.0, and the other having 5.6. picture att
SIZIF [17.4K]

<u>Given</u>:

Given that the two sides of the triangle are x, 4.0 and 5.6

We need to determine the range of possible sizes for the side x.

<u>Range of x:</u>

The range of x can be determined using the triangle inequality theorem.

The triangle inequality theorem states that, "if any side of a triangle must be shorter than the other two sides added together".

Thus, applying the theorem, we have;

x=4.0+5.6

x=9.6

Also, the the triangle inequality theorem states that, "the third side must be also larger than the difference between the other two sides".

Thus, we have;

x=5.6-4.0

x=1.6

Thus, the range of possible values for x are 1.6

5 0
3 years ago
Is the decimal form of 13/3 a rational number
Rus_ich [418]
No it wont be a rational number
8 0
3 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
1 year ago
Let A be a 3 by 6 , B be a 6 by 7 and C be a 7 by 3 matrix. Determine the size of the following matrices (if they do not exist,
kozerog [31]

Answer:

a. AB: 3 by 7

b. BA: N by N

c. A^TB: N by N

d. BC: 6 by 3

Step-by-step explanation:

Given

A =3\ by\ 6

B =6\ by\ 7

C =7\ by\ 3

Required

The dimension of the following matrices

As a general rule:

For A * B to be successful, the columns in a must equal the rows in B

Using this rule, we have:

A_{m*n} * B_{n * p} = AB_{m*p}

So:

(a)\ AB

A_{3*6} * B_{6*7} \to AB_{3 * 7}

(b)\ BA

B_{6*7} * A_{3*6} \to AB_{N * N}

The column numbers of B does not equal the row numbers of A.

Hence, BA does not exist

(c)\ A^TB

A^T implies that:

If A =3\ by\ 6, then

A^T = 6\ by\ 3

So:

A^T_{6*3} * B_{6,7} \to A^TB_{N*N}

The column numbers of A^T does not equal the row numbers of B.

Hence, A^TB does not exist

(d)\ BC

B_{6*7} * C_{7*3} \to BC_{6,3}

6 0
3 years ago
The stem-and-leaf plot shows the amount of money each student in Spanish club collected for charity this semester. How many male
HACTEHA [7]
72 because I helped you show do you Andreas show me too
7 0
2 years ago
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