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Y_Kistochka [10]
3 years ago
14

What is the area of a triangle with side that are 10 10 and 16

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

16√231 units²

Step-by-step explanation:

Because the triangle is isosceles, we can easily find the height. Splitting the triangle in half gives us a right triangle whose hypotenuse is 10 units, and one of the legs is 5 units.

We can use the Pythagorean Theorem: x² + 5² = 16² -> x² = 231 -> <em>x = √231</em> (can not be simplified)

Now that we know the height, we can solve for the area. The base is 16, and the height is √231.

That gives us 16*√231 = 16√231 units².

(Heron's formula can be used, but in this situation, doing this takes less time)

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Answer:

12m²

Step-by-step explanation:

For a rectangle, with length L and width W,

the perimeter is given as

Perimeter,

P = (2 x Length)  + (2 x Width)

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It is given that the perimeter is 48, hence

48 = 2L + 2W   (divide both sides by 2)

24 = L + W

or

L = 24 - W -----> eq 1

Also realize that the Area of a Rectangle is given by

A = L x W  -----> eq 2

Substituting eq 1 into eq 2,

A = (24 - W) x W

A = -W² + 24W

Recall that for a quadratic equation y = ax² + bx + c, the maxima or minima is given by y(max) =  -b/2a

In this case, b = 24 and a = -1

-b/2a = -24/[ 2(-1) ] = 12

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3 years ago
What types of symmetry does a triangle have
vredina [299]

Answer:

Equilateral Triangle, Isosceles Triangle, Scalene Triangle

Step-by-step explanation:

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4 years ago
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I got 2/7 for this one.
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