Question

Jamal is skating on a sidewalk. His initial velocity is 0.0 m/s; 35 seconds later his velocity is 5.0 m/s. What is his acceleration? -0.14 m/s/s -7 m/s 0.14 m/s/s 7 m/s

Answer 1

Answer:

answer is 0.1428

Explanation:

Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²

Answer 2

Answer:

$0.14m/s/s$ or $0.14m/s^2$

Explanation:

Acceleration is the rate at which the velocity of a body increases per unit time. Its S.I unit is meters per second per second. Mathematically it is given as follows;

$a=\frac{v_1-v_o}{t}............(1)$

where $v_1$ is the velocity, $v_o$ the initial velocity and t is the time taken.

Given;

$v_o=0.0m/s\\v_1=5.0m/s\\t=35s\\a=?$

We substitute all into equation (1) to calculate a as follows;

$a=\frac{5.0-0.0}{35}\\a=\frac{5}{35}\\a=\frac{1}{7}\\a=0.14m/s/s$