Question

A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0

Answer 1

Answer:

a)   $A=5m/s^2$

b)   $V=25m/s$

Explanation:

From the question we are told that:

Velocity $v=90km/h=25m/s$

Time $t=5.0s$

a)

Generally From Newton's motion equation for Average acceleration is   mathematically given by

  $A=\frac{V-U}{t}$

Since its from Rest Therefore

  $U=0$

 $A=\frac{25m/s-0}{5s}$

 $A=5m/s^2$

b)

Generally the equation for Average Velocity is mathematically given by

  $V=u+at$

 $AT t=1.0s\\\\V=0+5(1)$

 $V=5m/s$

 $AT t=2.0s\\\\V=0+5(2)$

 $V=10m/s$

 $AT t=5.0s\\\\V=0+5(5)$

 $V=25m/s$