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alexgriva [62]
3 years ago
7

Factor completely, then place the factors in the proper location on the grid. 3y4 - 2y2 - 5

Mathematics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

(3y^2-5)(y^2+1)

Step-by-step explanation:

Let's see if we can think of two numbers that multiply to be 3(-5)=-15

andd add up to be -2

How about -5 and 3? That work's! :)

3y^4-5y^2+3y^2-5

Factor by grouping!

y^2(3y^2-5)+1(3y^2-5)\\(3y^2-5)(y^2+1)

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irinina [24]

Answer:

the answer is $1920

Step-by-step explanation:

4% of $2000 is $80 so if they take 4% its just $2000 - $80 = $1920

Hope this helped! <3

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3 years ago
One paper clip has alength of 1/10 foot. all of sam's paper clips lined up endto end measure 5 feet long.how many paper clips do
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If one paper clip has a length of 1/10 foot than 10 paper clips would make 1 foot.
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Answer this ASAP I really need it
Ede4ka [16]
Given the expression
-2 + 6.45z - 6 + (-3.25z)

First, classify like terms, constant with constant, coefficient-variable with coefficient-variable
-2 + 6.45z - 6 + (-3.25z)
= 6.45z + (-3.25z) - 2 - 6

Second, combining like terms
= 6.45z + (-3.25z) - 2 - 6
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3 years ago
The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
LiRa [457]

Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.  

From the central limit theorem we have the formula:

z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }

a) z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40

The area to the left of z=2.40 is 0.9918

The area to the right of z=2.40 is 1-0.9918=0.0082

\therefore P(\bar X\:>\:1224)=0.0082

b) z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00

The area to the left of z=3.00 is 0.9987

\therefore P(\bar X\:

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

z=\frac{1214-1200}{\frac{60}{\sqrt{36} } }=1.40

The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

P(1200\:

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000

e) z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

5 0
3 years ago
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