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3 years ago

6

If a corporate bond with face value of $1,000 has an interest rate of seven percent paid once a year for a term of 10 years, wha

t is the size of the coupon payment? $1,000 $700 $70 $7

1 answer:

KiRa [710]3 years ago

4 0

I believe the answer is $700.

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This video, carl describes paas, a type of cloud computing in which the customer provides the application software and data,

stepan [7]

Cloud computing company provides the information

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3 years ago

You are analyzing two companies that manufacture electronic toys – Like Games Inc. and Our Play Inc. Like Games was launched eig

frosja888 [35]

Answer:

A <u>LOW</u> days of sales outstanding represents an efficient credit and collection policy. Between the two companies, <u>Like Games</u> is collecting cash from its customers faster than Our Play, but both companies are collecting their receivables less quickly that the industry average. <u>(5.51 days)</u>

Our Play’s fixed assets turnover ratio is <u>lower</u> than that of Like Games. This could be because Our Play is a relatively new company, so the acquisition cost of its fixed assets is <u>higher</u> than the recorded cost of Like Games’s net fixed assets.

Like Games’s total assets turnover ratio is <u>1.05x</u>, which is <u>lower</u> than the industry’s average total assets turnover ratio. In general, a higher total assets turnover ratio indicates greater efficiency.

Explanation:

DSO

Like Game 365 / (100,000 / 2,700) = 9.855

Our Play 365 / (100,000 / 3,900) = 14.235

Average 365 / (255,000/3,850) = 5.510

Fixed assets turnover:

LG 100,000 /55,000 = 1.82

100,000 / 95,000 ) = 1.052

average 255,000 / 234,600 = 1.087

OP 80,000 /55,000 = 1.45

Avg 255,000 / 216,750 = 1.18

4 0

3 years ago

Consider this problem: Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil an

astraxan [27]

Answer:

The maximum time guaranteed = 19.04 minutes.

Explanation:

From the given problem data, we have:

Let Y be the random variable which follows the normal distribution.

So,

Y ~ N(u = 15, SD = 2.4

Where, u = mean and SD = Standard Deviation

Let the maximum time guaranteed is = M

So,

P (Y > M) = 0.05 equation 1

Convert this equation 1 into standard normal variable, that is,

P(Y> M) = 0.05

1 - P(Y $\leq$ M) = 0.05

P(Y $\leq$ M) = 1 - 0.05

P(Y $\leq$ M) = 0.95

P $(\frac{Y-u}{SD} \leq \frac{M-u}{SD} )$ = 0.95

P ( Z $\leq \frac{M - 15}{2.4}$ ) = 0.95 Equation 2

From the equation 2, we have,

$\frac{M-15}{2.4}$ = 1.644853627

1.644853627 value is from using the function of Excel

( =NORSINV(0.95)) = 1.644853627

So,

M = 1.644853627 + 2.4 + 15

M = 19.04

Hence, the maximum time guaranteed = 19.04 minutes.

6 0

3 years ago

Select two skills and two personal values that you feel you have to offer in the workplace. Discuss the importance of these skil

klemol [59]

For me the two personal values its to bring Sarcastic Humor to the work place and Value to make hard descisions. Why are these things inportant? Well because If you bring comedy it boosts moral in the office and the ability to make hard desicions is useful to get a higher postion in your job.

6 0

3 years ago

The stock of Business Adventures sells for $50 a share. Its likely dividend payout and end-of-year price depend on the state of

Delvig [45]

Answer:

Holding period return = 14.49%, Standard Deviation = 11.08 approx

Explanation:

Eco Scenario Dividend Stock Price HPR Prob Expected HPR

Boom 3 60 26 0.33 8.58

Normal 1.2 58 18.4 0.33 6.072

Recession 0.75 49 (0.5) 0.33 <u> (0.165)</u>

Expected HPR 14.49%

<u>Calculation Of Standard Deviation</u>

(A) (B) (A) - (B)

$P_{1}$ $P_{0}$ $D_{1}$ Given return Exp return d p $p.d^{2}$

60 50 3 26 14.49 11.51 0.33 43.718

58 50 1.2 18.4 14.49 3.91 0.33 5.045

49 50 0.75 (0.5) 14.49 14.99 0.33 <u> 74.15</u>

Total $p.d^{2}$ = 122.91

wherein, d = deviation

p = probability

Standard Deviation = $\sqrt{Total\ p.d^{2} }$ = $\sqrt{122.91}$ = 11.08

<u></u>

<u>Working Note</u>:

Holding period return = $\frac{P_{1}\ -\ P_{0} \ +\ D_{1} }{P_{0} }$

Boom = $\frac{60\ -\ 50 \ +\ 3 }{50 }$ = 26%

Similarly, for normal = $\frac{58\ -\ 50 \ +\ 1.2 }{50 }$ = 18.4%

Recession = $\frac{49\ -\ 50 \ +\ 0.75 }{50}$ = (0.5)%

figure in bracket indicates negative return

7 0

3 years ago