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ioda
3 years ago
8

Mendel found that if parents both heterozygous for two traits are crossed, the resulting phenotypic ratio will be 9:3:3:9.

Biology
2 answers:
Anna [14]3 years ago
8 0
I think the answer is true, I hope this helps friend.
Lynna [10]3 years ago
6 0

Answer: False. The correct ratio is 9:3:3:1

There are two traits being crossed here: color and texture. When both parents as heterozygous for two traits are crossed, as a result four different types of plants are produced phenotypically in the ratio 9:3:3:1.

For example, two heterozygous pea plants with round and yellow seeds (RrYy x RrYy) are crossed then round yellow (9), round green (3), wrinkled yellow (3) and wrinkled green (1) seeds are produced. This is the result of Mendel’s Dihybrid cross.

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Answer:

In the F1 generation

RR = 0%

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Explanation:

A pink flowering plant has the genotype Rr. It is heterozygous for the allele. The alleles for this gene appears to show incomplete dominance, as the heterozygous phenotype is a blend of the two homozygous genotypes.

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A punnet square of the cross is shown.

The resulting punnet square shows that only Rr and rr genotypes are possible, at a ratio of 50:50 (or 1:1). Therefore, the genotype frequency of Rr is 50%, and rr is 50% in the F1 generation. This can also be written as 0.5. It is not possible to get a red plant, as the genotype RR can not come from this cross

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2 years ago
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Answer:

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Explanation:

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Given that one amino acid imparts 110 units to the molecular weight of the protein, the protein with 266 amino acids have the molecular weight= 266 x 110 = 29260, that is about 30,000.  

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