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Rzqust [24]
3 years ago
14

An above-ground swimming pool in the shape of a cylinder has a diameter of 16 feet and a height of 5 feet. If the pool is filled

with water to 1.5 inches from the top of the pool, what is the volume, to the nearest cubic foot, of the water in the pool?⇆
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer is lots of god Which equation is the inverse of <em>y </em>= 100 – <em>x</em>2?









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The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
Help pls I dont know​
liubo4ka [24]
14 and -18 would be less than or equal too when the -y makes them -14 and 18 it is still less than 19
5 0
3 years ago
Read 2 more answers
What is the nth derivative of sin^3x?
Marrrta [24]
2??????..... idk ._.
6 0
3 years ago
Find each missing measure.
sertanlavr [38]

Answer:

Step-by-step explanation:

60° , 60° , 60°

8 0
3 years ago
The perimeter of a rectangle is 150 cm. the length is 4 cm greater than the width find the width and length
Fudgin [204]

Let's call the width of our rectangle w and the length l. We can say l = w + 4, since the length is equal to 4 cm greater than the width.


Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or P = 2l + 2w. To solve this problem, we can substitute in the information we know, as shown below:

150 = 2(w + 4) + 2w

150 = 4w + 8

142 = 4w

w = \frac{71}{2}


Now, we can substitute in the width we found into the formula for length, which is l = w + 4:

l = \frac{71}{2} + 4

l = \frac{79}{2}


The width of our rectangle is \boxed{\frac{71}{2} \,\, \textrm{cm}} cm and the length of our rectangle is \boxed{\frac{79}{2} \,\, \textrm{cm}}

8 0
3 years ago
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