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3 years ago

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An above-ground swimming pool in the shape of a cylinder has a diameter of 16 feet and a height of 5 feet. If the pool is filled

with water to 1.5 inches from the top of the pool, what is the volume, to the nearest cubic foot, of the water in the pool?⇆

1 answer:

vagabundo [1.1K]3 years ago

4 0

Answer is lots of god Which equation is the inverse of <em>y </em>= 100 – <em>x</em>2?

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Let f(x) = x2 − 3x − 7. Find f(−3).

MrRa [10]

Answer is:
f(-3) = 11

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3 years ago

Read 2 more answers

Can someone solve this question to me.i will mark brainliest. :)

Alex787 [66]

Answer:

Parent Function: $y=\sqrt{x}$
Horizontal shift: right 3 units
Vertical shift: up 3 units
Reflection about the x-axis: none
Vertical strech: streched

Step-by-step explanation:

assume that $y=\sqrt{x}$ is $f(x)=\sqrt{x}$ and $y=\sqrt{-2x+6}+3$ is

$g(x)=\sqrt{-2x+6}+3\\ f(x)=\sqrt{x} \\g(x)=\sqrt{-2x+6}+3$

The transformation from the first equation to the second equation can be found by finding a,h and k for each equation.

$y=a\sqrt{x-h}+k$

factor a 1 out of the absolute value to make the coefficient of x equal to 1

$y=\sqrt{x}$

factor a 2 out of the absolute value to make the coefficient of x equal to 1

$y=\sqrt{2}\sqrt{x-3}+3$

find a, h and k for $y=\sqrt{2}\sqrt{x-3}+3$

$a=1.41421356\\ h=3\\k=3$

the horizontal shift depends on the value of h when $h > 0$ , the horizontal shift is described as:

$g(x)=f(x+h)$ - the graph is shifted to the left h units

$g(x)=f(x-h)\\$ - the graph is shifted to the right h units

the vertical shift depends on the value of k

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1 year ago

Oxana [17]

I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct

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3 years ago

What is the most reasonable answer for PI squared?

Daniel [21]

Answer:

9.87

Step-by-step explanation:

usually in math you never have to write down what pi squared is, you just have it incorporated into your equations. But here is the best written answer.

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2 years ago

Find the root of 11+2square30

EleoNora [17]

$\\ \sf\longmapsto \sqrt{11+2^230}$

$\\ \sf\longmapsto \sqrt{11+4(30)}$

$\\ \sf\longmapsto \sqrt{11+120}$

$\\ \sf\longmapsto \sqrt{131}$

$\\ \sf\longmapsto 11.3$

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2 years ago