Standard form Ax + By = C
so
<span>(y - y1) = m(x - x1)
</span>given (5, -7) and m = -1/5
so
y + 7 = -1/5(x - 5)
-5y - 35 = x - 5
x + 5y = -30
answer
d. x + 5y = -30
<span>6n – 11 > 31
</span><span>6n > 31 + 11
</span>6n > 42
n > 42/6
n > 7
Let H represent heads and T represent tails.
Writing HH means we get two heads and HT means we get heads first, then tails second, and so on.
We have these four possible outcomes when flipping two coins
Of those four outcomes, two of them have exactly one head show up (HT and TH). The probability of getting exactly one head is 2/4 = 1/2, so this is why Jose is correct.
Well costheta=1, at 0, 2pi,...
knowing this we can exclude the first two as the are not undefined anywhere.
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
