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Setler [38]
3 years ago
9

Which statement is true if the Hrxn of a reaction is positive?

Chemistry
2 answers:
Sveta_85 [38]3 years ago
7 0
When the heat of reaction is positive, then the reaction is an endothermic reaction. It means that the heat is into the system. The reaction to occur heat should be supplied into the system. It is not a spontaneous reaction since the process absorbs energy to reach the activation energy.
Gnom [1K]3 years ago
7 0

Answer: answer is A

Explanation:

because the reaction will always be endothermic

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Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from the reaction of 5.8 moles of a
andrey2020 [161]
Answer:
2.9
Explanation:
1- we can see that for every 2 moles of aluminum hydroxide 1 mole of aluminum sulfate is made so we can make a relation

6 0
3 years ago
How do I write the formula for: Ferric hydrogen sulphate, Tungsten (V) peroxide, Nitric acid and Aluminum acetate? ...?
hram777 [196]
We write the following substances' chemical formula as follows:

Ferric hydrogen sulphate = Fe(HSO4)3.<span>
 
Tungsten (V) peroxide = </span>W2(O2)5<span>

Nitric acid = HNO3

Aluminum acetate = </span>C6H9AlO6

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7 0
3 years ago
What us the definition of half-life?
UNO [17]
Half-life is the time required for the amount of something to fall to half its initial value. This term is usually used in nuclear physics to describe how quickly unstable atoms undergo decay, or how long stable atoms survive, radioactive decay, and it is also used more generally of any type of exponential or non-exponential decay.

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7 0
3 years ago
For the following reaction, 5.22 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 12.9 grams of
Mamont248 [21]

Answer:

m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Explanation:

Hello,

In this case, the undergoing balanced chemical reaction is:

Al_2O_3(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2O(l)

Thus, as 5.22 grams of aluminium oxide reacts, the required yielded amount of aluminium sulfate results:

m_{Al_2(SO_4)_3}=5.22gAl_2O_3*\frac{1molAl_2O_3}{102gAl_2O_3}*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3}*\frac{342gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Moreover, the percent yield is:

Y=\frac{12.9g}{17.5g} *100\%=73.7\%

Best regards.

6 0
4 years ago
What types of solutions are made when the temperature increases, then decrease?
kati45 [8]
Answer:
b. Supersaturated
3 0
3 years ago
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