Answer:
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Explanation:
Hello,
At first, the molarities of NaClO and KF are computed as shown below:
Now, since both NaClO and KF are ionic, one proposes the dissociation reactions as:
In such a way, by writing the formation of HClO and HF respectively, due to the action of water, we obtain:
Now, the presence of OH⁻ immediately implies that Kb for both NaClO and KF must be known as follows:
In such a way, the law of mass action for each case is:
Now, by solving for the change for both the ClO⁻ and F⁻ equilibriums, we obtain:
Such results equal the concentrations of OH⁻ in each equilibrium, thus, the total concentration of OH⁻ result:
With which the pOH is:
And the pH:
In addition, the equilibrium concentrations of HClO and HF equals the change for each equilibrium as:
Best regards.
