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mr_godi [17]
3 years ago
11

When 1 mole of H2(g) reacts with F2(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved H2(g) + F

2(g2HF(g) Is this reaction endothermic or exothermic? What is the value of q?
Chemistry
1 answer:
topjm [15]3 years ago
7 0

Answer: The reaction is exothermic. The value of q is  -542 kJ.

Explanation:

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and  for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and  for the reaction comes out to be negative.

Thus H_2(g)+F_2(g)\rightarrow 2HF(g) evolves heat , it is exothermic in nature. The value of q is -542kJ.

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protons plus neutrons

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All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons.

The sum of neutrons and protons is the mass number of an atom.

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3 years ago
Question 4
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What is oxidized and what is reduced <br> C2H4 + 2O2 → 2CO + 2H2O<br> C2H4 + 3O2 → 2CO2 + 2H2O
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C2H4 is oxidized and O2 is reduced in both reactions.

<h3>What is oxidation/reduction?</h3>

Oxidation is defined in several ways. Some of the definitions are:

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Reduction, on the other hand, is defined as:

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In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.

The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.

More on oxidation and reduction can be found here: brainly.com/question/3867774

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2 years ago
Which condition increases the number of collisions between reactant molecules in a given volume?
Nezavi [6.7K]

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Increasing Surface Area

Explanation:

A greater surface area (meaning more, smaller particles) allows for more opportunity for particles to collide.  On the other hand, decreasing temperature and removing a catalyst would only decrease the number of collisions, and the clumping option doesn't make much sense.  Hope this helps!

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If the volume and Kelvin temperature are reduced by one-half what will happen to the pressure???
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