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Marat540 [252]
3 years ago
14

A line intersects the point (-3,-7) and has a slope of -1/3. What is the slope intercept equation for this line? Y = -X/3 -[?]

Mathematics
1 answer:
SashulF [63]3 years ago
7 0
First, you can plug this into the point slope formula. you will have to do that before you can get the slope intercept form. Plug in what you know. m is slope, so plug in -1/3 for m. The point given can be plugged in to the formula also. This is what it should look like:

y + 7 = -1/3(x + 3) 

***** Note that the -3 and -7 become positive because it is subtracting negative numbers and 2 negatives make a positive. *************************

Now distribute the -1/3 times x and 3. 

y + 7 = -1/3x - 1

Now to get y by itself, add 7 to both sides. 

y = -1/3x + 6

This is your answer: y = -1/3x + 6
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A long jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above an
slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Horizontal distance from the start line, measured in meters.

y - Height of the long jumper, measured in meters.

a, b, c - Polynomial constants, measured in \frac{1}{m}, dimensionless and meters, respectively.

If we know that (x_{1},y_{1}) = (3\,m, 0\,m), (x_{2},y_{2}) = (8\,m, 0.05\,m) and (x_{3}, y_{3}) = (9\,m, 0\,m), this system of linear equations is presented below:

9\cdot a + 3\cdot b + c = 0 (Eq. 1)

81\cdot a + 9\cdot b + c = 0 (Eq. 2)

64\cdot a + 8\cdot b + c = 0.05 (Eq. 3)

The coefficients of the polynomial are, respectively:

a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}

The equation of the parabola that models the path of the long jumper through the air is y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.

But we need y measured in centimeters, then, we use the following conversion:

y = 100\cdot y'

Then, we get that:

y = -x^{2}+12\cdot x -27

Where x and y are measured in meters and centimeters, respectively.

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

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Aneli [31]
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5 0
3 years ago
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

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2 years ago
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