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Marat540 [252]
3 years ago
14

A line intersects the point (-3,-7) and has a slope of -1/3. What is the slope intercept equation for this line? Y = -X/3 -[?]

Mathematics
1 answer:
SashulF [63]3 years ago
7 0
First, you can plug this into the point slope formula. you will have to do that before you can get the slope intercept form. Plug in what you know. m is slope, so plug in -1/3 for m. The point given can be plugged in to the formula also. This is what it should look like:

y + 7 = -1/3(x + 3) 

***** Note that the -3 and -7 become positive because it is subtracting negative numbers and 2 negatives make a positive. *************************

Now distribute the -1/3 times x and 3. 

y + 7 = -1/3x - 1

Now to get y by itself, add 7 to both sides. 

y = -1/3x + 6

This is your answer: y = -1/3x + 6
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\frac{8}{4/5}

Second Answer:

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which description best describes the solution to the following system of equations y= -2x +3 y= -x + 1
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For this case we have the following system of equations:
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y = -x + 1
 Equating the values of y we have:
 -2x +3 = -x + 1

 From here, we can clear the value of x.
 We have then:
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-x = -2

x = 2
 Then, we look for the value of y.
 For this, we substitute x in any of the equations:
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y = -2 + 1

y = -1
 Answer:
 
The ordered pair solution of the system of equations, is given by:
 
(x, y) = (2, -1)
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2 years ago
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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
2 years ago
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