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vesna_86 [32]
3 years ago
12

A pizzeria sells a round pizza with a diameter of 16 inches. Another pizzeria sells a large square pizza with a side length of 1

5 inches Which of the two shapes gives you more pizza? How much more? Rounded to the nearest hundredth.
Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

pizzeria1

Step-by-step explanation:

Given data

pizzeria1

Diameter=16in

Radius= 16/2= 8in

Area= πr^2

Area= 3.132*8^2

Area= 201.09 in^2

pizzeria2

Diameter=15in

Radius= 15/2= 7.5in

Area= πr^2

Area= 3.132*7.5^2

Area= 176.74n^2

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MAXImum [283]

The translation is The figure moves left and down.

Option:B.

<u>Step-by-step explanation:</u>

The given coordinate  (x,y) is mapped and it gets translated using mapping (x+a,y+b).

Also, we are given with information that the value of a and also value of b is negative (-a,-b).

⇒the mapping coordinate = (x+(-a),y+(-b)).

The mapping coordinate = ( x-a, y-b).

The coordinate points will be decreasing in x and y axis. So it will move towards the left and downside of the graph.

For example,

Consider that a= -3 and b= -2.

∴The translating coordinate will be (x-3,y-2).

Choose a coordinate point ( 2,2) initially.

Substitute the x,y coordinate in the translating coordinate.

⇒ (x-3,y-2) = (2-3,2-2).

=(-1,0).

After translation the points will be (-1,0).

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6 0
3 years ago
Read 2 more answers
A climber on Mt Everest is 6000 meters from the start of his trail and at elevation 8000 meters above sea level. At x meters fro
sergeinik [125]

Answer:

h'(x) = 0.6 and Δx = 1 and 2

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Explanation below:

Step-by-step explanation:

Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.

We know that the function for elevation is given by h(x) where x is the number of meters from the start.

Therefore, h(6000) = 8000.

We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)

We need to use the derivative at a point to estimate values of the function at nearby points

We're going to use h'(x)= 0.6. Δx= 1

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

Therefore h (6001) = 8,000.6

Now for h'(x)= 0.6. Δx= 1

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Therefore h(6002) = 8001.2

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3 years ago
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For the answer to the question, what is the range of actual weights of the object if t<span>he weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 lbs.?
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3 years ago
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