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vitfil [10]
4 years ago
7

{2, 9, 10, 1,9, 8, 10,3, 5, 5, 10, 2, 4, 5, 6,4} Which dot plot represents this data?

Mathematics
1 answer:
skad [1K]4 years ago
6 0

Answer:

well idk which dot plot it would be cuz you didnt give me

Step-by-step explanation:

But it would have one dot on the 1, 3 dots on the 2, 1 dot on 3, 2 dots on the 4, 3 dots on the 5, 1 dot on the 6, 0 dots on the 7, 1 dot on the 8, 2 dots on the 9, and 3 dots on the 10

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The solution set of 4x-(x+7)=2(x+3)​
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Step-by-step explanation:

<h3><u>To</u><u> </u><u>Solve</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

<h3><u>SOL</u><u>UTION</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

\\ \tt{:}\leadsto 4x-x-7=2x+6

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3 years ago
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Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

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The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
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melomori [17]

Answer:

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lilavasa [31]

Answer:

Correct option is:

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Step-by-step explanation:

A hypothesis for the proportion of people who include locally grown foods in their diets can be defined as:

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<em>Hₐ</em>: The proportion of people who include locally grown foods in their diets is difference from <em>p</em>.

The decision rule can be based on the 95% confidence interval.

If the confidence interval consists the hypothetical value of the true proportion then the null hypothesis will be accepted or else the null hypothesis will be rejected.

The 95% confidence interval for the proportion of all people in the country who try to include locally grown foods in their diets is given as (0.70, 0.76).

This interval implies that there is 0.95 probability that the true proportion of people who include locally grown foods in their diets is between 70% and 76%.

Assuming that the claim made was supported by the 95% confidence interval.

The claim should be:

Less than 75% of all people in the country try to include locally grown foods in their diets.

Because the 95% confidence interval defines the range of the true proportion as 70% to 76%. Most of the values are below 75%.

Thus, the correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

3 0
3 years ago
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