All categories

2 years ago

Find the percent of change from 18 to 12.

Mathematics

1 answer:

melomori [17]2 years ago

8 0

Answer:

18 is the old value and 12 is the new value. In this case we have a negative change (decrease) of -33.33333333 percent because the new value is smaller than the old value.

You might be interested in

ILL GIVE BRAINLEST, please no links and explain please:)

Veseljchak [2.6K]

Answer:

180

Step-by-step explanation:

I need to draw a picture to explain.

4 0

3 years ago

A kite with a string 100 feet long makes an angle of elevation of 50° with the ground, assuming the string is straight, how high

erik [133]

Sin(θ)=o/h
sin(50)=x/100
.76604*100=x=76.604

4 0

3 years ago

Explain how you can use doubles when multiplying with4 to find 4x8?

Soloha48 [4]

Using 4x6=24. double the factor four to get eight double the factor 24 to get 48

3 0

2 years ago

the three angles of a quadrilateral are 29 degrees 31 degrees and 144 degrees respectively. Find the fourth angle

FinnZ [79.3K]

Answer:

156 degrees

Step-by-step explanation:

The four angles in any quadrilateral add to 360 degrees. Add the given degrees and subtract that number from 360 for your answer

3 0

3 years ago

Consider a series system composed of 4 separate components where each component has a 30% chance of failing. Assume each compone

Marina86 [1]

Answer:

16.15% probability that exactly 3 of them would function

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of each system working:

4 components, which means that $n = 4$

Each has a 30% probability of failing, so $p = 1 - 0.3 = 0.7$

For the system to work, all 4 components have to work. This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401$

0.2401 probability of a system working.

If you have 7 of these systems, what is the probability that exactly 3 of them would function?

Now 7 systems, so $n = 7$

0.2401 probability of a system working.

We have to find P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.2401)^{3}.(0.7599)^{4} = 0.1615$

16.15% probability that exactly 3 of them would function

5 0

3 years ago