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dybincka [34]
3 years ago
11

What is the following number in decimal form?

Mathematics
1 answer:
aleksley [76]3 years ago
6 0
8.8 because you need to multiply 1.68 by 10 which is 16.8-8=8.8

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-2/3+(-1/6) <br><br> -1/4+(-3/8) <br><br> -1/4+(-1/2) <br><br> Need answers to all of them!!
miss Akunina [59]

Answer:

Step-by-step explanation:

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3 years ago
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PLEASE HELP!!!!!The volume of a cube is represented by the expression below, where s is the side length of the cube.
barxatty [35]

Answer:

D. 216 cubic centimetres.

Step-by-step explanation:

The answer is D, because 6 to the 3rd power is 216.  therefore, if the side length is 6, the answer is 216.

7 0
3 years ago
Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).
Sergio [31]
Hello,

Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3

y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)

Answer B.

3 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
Find the equation of the line passing through the points (7, 16) and (2, −4). Then state the slope and coordinates of the x- and
Elanso [62]

Answer:

Equation point-slope model is: y-16 = 4 (x-7)

Slope =4

x-intercept=(7,2)

y-intercept=(16,-4)

Step-by-step explanation:

6 0
3 years ago
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