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3 years ago

A pre-algebra book is 8 1 half inches by 9 1 fourth inches. Determine the perimeter of the textbook.

Mathematics

1 answer:

Arisa [49]3 years ago

8 0

Answer:

Rectangular book--

two 8 1/2 sides

two 9 1/4 sides

8 1/2*2=17

9 1/4*2=18 1/2

17+18 1/2= 35 1/2

The perimeter of the textbook is 35 1/2 inches or 35.5 inches.

-this is not mine btw creds to sunflowerem :))

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kompoz [17]

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Substituting with m = 1 and the point (4, 8) into the general equation, we get:

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y = x + 4

b. To graph the line y = x + 4, we need to draw two points and then connect them with a line. Replacing with x = 0 into the equation:

y = 0 + 4

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attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: $\frac{x}{12\pi } = \frac{130}{360}$

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) $\frac{arclength}{2\pi.r } = \frac{mAB}{360}$ , where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = $\frac{mAB.2.\pi.r }{360}$

arc length = $\frac{90.2.3.14.6}{360}$

arc length = 9.4

The arc lenght for the image is 9.4 inches.

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$\frac{x}{2.6.\pi } = \frac{130}{360}$