Answer:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29%20%3D%200.8708)
And the best option would be:
![0.8708](https://tex.z-dn.net/?f=%200.8708)
Step-by-step explanation:
We assume that the distribution for the random variable is:
![X \sim N (\mu=0 , \sigma=1)](https://tex.z-dn.net/?f=%20X%20%5Csim%20N%20%28%5Cmu%3D0%20%2C%20%5Csigma%3D1%29%20)
For this case we want to calculate the following probability:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29)
And we can use the normal standard distribution or excel and we got:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29%20%3D%200.8708)
And the best option would be:
![0.8708](https://tex.z-dn.net/?f=%200.8708)
KE = 1/2(m * v^2)
KE = 1/2(1350 * 12^2)
KE = 1/2(1350 * 144)
KE = 1/2(194,400)
KE = 97,200 Joules
Well x=19/3
Decimal form is 0.6333333....
Answer:
3/5
Step-by-step explanation:
sin theta=opposite/hypotenuse
4/5=opposite/hypotenuse
therefore opposite=4 and hypotenuse=5
for adjacent
using pythagoras theorem
a^2+b^2=c^2
opposite^2 + adjacent^2 =hypotenuse^2
4^2 + adjacent^2 =5^2
16 + adjacent^2 =25
adjacent^2 =25-16
adjacent =![\sqrt{9](https://tex.z-dn.net/?f=%5Csqrt%7B9)
adjacent=3
cos theta=adjacent/hypotenuse
=3/5
therefore the value of cos theta is 3/5