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Inessa [10]
2 years ago
7

The ratio of the income of two persons is 4:3. Each of them saves RS 200 yearly. find their yearly income​

Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0
I need points im sorry
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What is the solution set for -4x - 10 ≤ 2?
hichkok12 [17]

Answer:

x <u>></u> -3

Step-by-step explanation:

- 4x - 10 <u><</u> 2

     + 10 <u><</u> + 10

<u>- 4x < 12</u>

-4      -4

x <u>></u> -3

I think the sign flips because the negative sign is w/the X.... If it doesn't, sorry 4 being wrong...

8 0
3 years ago
3[–x + (2 x + 1)] = x – 1
photoshop1234 [79]

Answer:

<h3>x = -2</h3>

Step-by-step explanation:

3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\

Collect like terms

3x -x =-1-3

Add similar elements

2x = -4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{-4}{2}\\\\Simplify\\\\x = -2

3 0
3 years ago
Based on the given information, what can you conclude and why
Dmitry_Shevchenko [17]
Notice the point R
is a vertex between two "vertical angles" \measuredangle SRT\ and\ \measuredangle QRP

those two folks are also the same
so now, we have the left triangle has angle P equals to angle T on the other triangle
we also have the side on the left triangle of PR equals the side of TR on the other triangle, and those two verticals angles are equal to each other

does ASA ring a bell?
8 0
3 years ago
The information below explains the transformations and translations of a logarithmic function. What is the equation for this fun
maks197457 [2]

The transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>How to transform the logarithmic function?</h3>

The parent logarithmic function is

y = log(x)

When shifted left by 4 units, we have:

y = log(x + 4)

When shifted up by 3 units, we have:

y = log(x + 4) + 3

When compressed vertically by 1/3, we have:

y = 1/3(log(x + 4) + 3)

This gives

y = 1/3(log(x + 4)) + 1

When stretched horizontally by 3, we have:

y = 1/3(log(x/3 + 4)) + 1

Hence, the transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>The transformation of function f(x)</h3>

We have:

f(x) = log[-(x – 5)] + 4

Set the radicand greater than 0

-(x - 5) > 0

Divide by -1

x - 5 < 0

Add 5 to both sides

x < 5 -- this represents the domain

A logarithmic function can output any real number.

So, the range is -\infty < f(x) < \infty

In the domain, we have:

x < 5

This means that the interval of decrease is -\infty < x < 5

Rewrite as an equation

x = 5 --- this represents the equation of asymptote

Read more about logarithmic functions at:

brainly.com/question/12708344

#SPJ1

6 0
1 year ago
Solve. Good luck! Please do not try to google this.
Elena L [17]
\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}
\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}
\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}
3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)
3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))
3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)
3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)
3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)
3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)
12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4
12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4
6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)
6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)
5 0
3 years ago
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