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Anastaziya [24]
4 years ago
12

As baby boomers enter their golden years, the number of people afflicted with Alzheimer's disease is expected to rise dramatical

ly. In a study published in the Journal of Neurology, the number of people with Alzheimer's disease in the United States age 65 years and over is projected to be
N(t) = 0.00525t² + 0.075t + 4.7 (0 ≤ t ≤ 4)

millon in decate t, where t = 0 corresponds to 2010.

(a) What is the projected number of people with Alzheimer's disease in the United States age 65 and over in 2020? (Round your answer to four decimal places.)
_________ million
(b) How fast is the number of people with Alzheimer's disease in the United States age 65 years and over projected to grow in 2020?
_________ million
(c) How fast is the rate of growth of people with Alzheimer's disease in the United States age 65 years and over projected to change in the period covered by the study?
_________ million per decade per decade.
Mathematics
1 answer:
dybincka [34]4 years ago
4 0

Answer:

Step-by-step explanation:

Given that the number of people with Alzheimer's disease in the United States age 65 years and over is projected to be

N(t) = 0.00525t^2 +0.075t+4.7,(0 ≤ t ≤ 4)

where N is in millions where year 2010 corresponds to t=0

For 2020, 10 years lapsed hence t= 1

a) N(1) = 0.00525(1)^2 + 0.075(1) + 4.7\\=4.78025

So 4.78025 million people

b) Growth = N(1)-n(0) =0.08025 million

c) N(4) = 5.084

Average rate of change = (5.084-4.7)/4 =0.096 million per decade

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An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
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Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

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3 years ago
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