Question

64a^3 b^3-125c^3 Which algebraic identity is used in this? Answer with steps

Answer 1

Answer:

$64a^3b^3-125c^3=(4ab-5c)(16a^2b^2+40abc+25c^2)$

Step-by-step explanation:

You have the following polynomial:

$64a^3b^3-125c^3$

This expression is of the form:

$x^3-y^3$

that is, a difference between cubes. The factorization of such a polynomial is given by:

$x^3-y^3=(x-y)(x^2+2xy+y^2)$

You apply the last expression to the polynomial given in the problem. But first you have:

$x^3=64a^3b^3\\\\y^3=125c^3\\\\x=4ab\\\\y=5c$

finally, you obtain:

$64a^3b^3-125c^3=(4ab-5c)((4ab)^2+2(4ab)(5c)+(5c)^2)\\\\64a^3b^3-125c^3=(4ab-5c)(16a^2b^2+40abc+25c^2)$