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4 years ago

I’m not sure what to do. Would someone please help me with the steps how to do this. Thank you

Mathematics

1 answer:

dimulka [17.4K]4 years ago

7 0

Draw the graph:

f(x) = x+1 for x< -1

f(x) = x2 + 3 for x>=-1

(Remember the graph should be in the range of x) After drawing the graph you will get a solution for domain and range.

For part c,d,e:

c. f(-10), meaning x = -10 and find y.

if x = -10 you will use the first equation f(x) = x+1 because x is less than -1.

f(-10) = -10 + 1

=-9

do something for d,e.

//Hope it helps, let me know for more help if needed.

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Answer:

See below

Step-by-step explanation:

By using the table 1 attached (See Table 1 attached)

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$\bf y=m_{yx}x+b_{yx}$

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Note: Be careful not to confuse

$\bf \sum x^2$ with $\bf (\sum x)^2$

Performing our calculations we get:

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$\bf b_{yx}=\frac{10*923-(95)(83)}{10(1277)-(95)^2}=0.3591$

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Now, to find the line that relates x as a function of y, we simply switch the roles of x and y in the formulas.

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(x=response variable, y=explanatory variable)

$\bf x=m_{xy}y+b_{xy}$

where

$\bf m_{xy}$ is the slope of the line

$\bf b_{xy}$ is the x-intercept

In this case we use these formulas:

$\bf m_{xy}=\frac{(\sum x)(\sum y)^2-(\sum y)(\sum xy)}{n\sum y^2-(\sum y)^2}$

$\bf b_{xy}=\frac{n\sum xy-(\sum x)(\sum y)}{n(\sum y^2)-(\sum y)^2}$

n = 10 is the number of observations taken (pairs x,y)

Note: Be careful not to confuse

$\bf \sum y^2$ with $\bf (\sum y)^2$

Remark: If you wanted to draw this line in the classical style (the independent variable on the horizontal axis), you would have to swap the axis X and Y)

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$\bf m_{xy}=\frac{(95)(83)^2-(83)(923)}{10*743-(83)^2}=1068.1072$

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3 years ago