Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Https://us-static.z-dn.net/files/d8d/e008ced388704d59896d3bf37158f465.jpeg
Answer: 12 cm
Step-by-step explanation:
The masses of the spheres are proportional to their volums, and the cube of the ratio is k^3=135/5=27 ==> k=3
The greater radius is 3*4=12 (cm)
the q3 is just above the median so
Step-by-step explanation:
its higher by 5
Answer:
x=4
Step-by-step explanation:
We can find the length of RT by using the Pythagorean theorem
sin theta = opposite side/ hypotenuse
sin 60 = 2 sqrt(3)/ RT
Multiply each side by RT
RT sin 60 = 2 sqrt(3)
Divide by sin 60
RT = 2 sqrt(3)/ sin 60
RT = 4
Then
tan theta = opposite side/ adjacent side
tan 45 = x/RT
tan 45 = x/4
4 tan 45 = x
4 = x