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Rudik [331]
3 years ago
14

Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, 0), and S (1, −1). Russell and Jamie have both classified PQRS differ

ently. Examine their proofs. Who is correct?
Russell Jamie
PQRS is a parallelogram because opposite sides are both congruent and parallel.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. PQRS is a rectangle because opposite sides are both congruent and parallel and adjacent sides are perpendicular.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. Segments PS and SR are perpendicular. Segments PQ and QR are perpendicular.
Russell
Jamie
Both
Neither
Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0

Jamie

Step-by-step explanation:

dybincka [34]3 years ago
3 0

Answer: Jamie

Step-by-step explanation:

Bcuz I took the test and made sure it was Jamie

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If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?​
Dimas [21]

Answer:

Equilateral Triangle

Side a = 1

Side b = 1

Side c = 1

Angle ∠A = 60° = 1.0472 rad = π/3

Angle ∠B = 60° = 1.0472 rad = π/3

Angle ∠C = 60° = 1.0472 rad = π/3

C=60°B=60°A=60°b=1a=1c=1

Area = 0.43301

Perimeter p = 3

Semiperimeter s = 1.5

Height ha = 0.86603

Height hb = 0.86603

Height hc = 0.86603

Median ma = 0.86603

Median mb = 0.86603

Median mc = 0.86603

Inradius r = 0.28868

Circumradius R = 0.57735

Vertex coordinates: A[0, 0] B[1, 0] C[0.5, 0.86603]

Centroid: [0.5, 0.28868]

Inscribed Circle Center: [0.5, 0.28868]

Circumscribed Circle Center: [0.5, 0.28868]

Step-by-step explanation:

6 0
3 years ago
State the domain and the range of the graph of f(x) = 4
Anastaziya [24]
Domain: (-infinity, infinity)
range: (-infinity, infinity)
7 0
3 years ago
What is the solution to the following system of equations? x − 4y = 6 2x + 2y = 12 (0, 10) (10, 0) (6, 0) (0, 6)
frozen [14]

Answer:

(6,0)

Step-by-step explanation:

The given system has equations:

x-4y=6

2x+2y=12

Multiply the top equation by 2 to get:

2x-8y=12

2x+2y=12

Subtract the top equation form the bottom equation to get:

2x-2x+2y--8y=12-12

\implies 10y=0

\implies y=0

Put y=0 into x-4y=6

x-4*0=6

\implies x=6

Therefore the solution is (6,0)

4 0
3 years ago
Soooo again in meters I'm soo sorryyy​
vovikov84 [41]

I think 710 is the answer

266+266+89+89= 710

8 0
3 years ago
A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?
stealth61 [152]
A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?

If it's 20 feet * 20 feet = to
400 sq.ft

Hope this helps!
6 0
3 years ago
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