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Rudik [331]
3 years ago
14

Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, 0), and S (1, −1). Russell and Jamie have both classified PQRS differ

ently. Examine their proofs. Who is correct?
Russell Jamie
PQRS is a parallelogram because opposite sides are both congruent and parallel.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. PQRS is a rectangle because opposite sides are both congruent and parallel and adjacent sides are perpendicular.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. Segments PS and SR are perpendicular. Segments PQ and QR are perpendicular.
Russell
Jamie
Both
Neither
Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0

Jamie

Step-by-step explanation:

dybincka [34]3 years ago
3 0

Answer: Jamie

Step-by-step explanation:

Bcuz I took the test and made sure it was Jamie

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Ultimately, the question is "What is 5% of $279.95?"

To answer this, multiply 279.95 by 5%, or 0.05 which is 5% in decimal form.

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Solve equations by using elimination <br> -4+5y= 13<br> X-5y=21<br> ( , )
tigry1 [53]

Answer:

y=17/5 ,x= 38

Step-by-step explanation:

-4+5y =13 add 4 both side

4-4+5y=13+4

5y=17

5y/5=17/5 y=17/5

x-5y=21

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5 0
2 years ago
PLEASE HELP:
Lady bird [3.3K]

Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.

Explanation:

(A)

From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).

If a shape rotate 90 degree counterclockwise about the origin, then,

(x,y)\rightarrow (-y,x)

J(-4,1)\rightarrow J'(-1,-4)

K(-4,-2)\rightarrow K'(2,-4)

L(-3,-1)\rightarrow L'(1,-3)

Therefore, the vertex of imare are  J'(-1,-4),  K'(2,-4) and  L'(1,-3). The graph is shown in figure (1).

(B)

If a figure reflect across the y-axis then,

(x,y)\rightarrow (-x,y)

J(-4,1)\rightarrow J''(4,1)

K(-4,-2)\rightarrow K''(2,-4)

L(-3,-1)\rightarrow L''(3,-1)

Therefore, the vertex of imare are  J''(4,1),  K''(2,-4) and  L''(3,-1). The graph is shown in figure (2).

8 0
3 years ago
A sample of 100 wood and 100 graphite tennis rackets are taken from the warehouse. If 15 wood and 14 graphite are defective and
ladessa [460]

Answer:

The probability that the racket is wood or defective is 0.57.

Step-by-step explanation:

Let W represents wood racket, G represents the graphite racket and D represents the defective racket,

Given,

n(W) = 100,

n(G) = 100,

⇒ Total rackets = 100 + 100 = 200

n(W∩D) = 15,

n(G∩D) = 14,

⇒ n(D) = n(W∩D) + n(G∩D) = 15 + 14 = 29,

We know that,

n(W∪D) = n(W) + n(D) - n(W∩D)

= 100 + 29 - 15

= 100 + 14

= 114,

Hence, the probability that the racket is wood or defective,

P(W\cup D) = \frac{114}{200}

=0.57

3 0
3 years ago
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