1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudik [331]
3 years ago
14

Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, 0), and S (1, −1). Russell and Jamie have both classified PQRS differ

ently. Examine their proofs. Who is correct?
Russell Jamie
PQRS is a parallelogram because opposite sides are both congruent and parallel.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. PQRS is a rectangle because opposite sides are both congruent and parallel and adjacent sides are perpendicular.

Segment PQ
P (0, 1) and Q (3, 2)
d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 2 minus 1 over 3 minus 0 equals one third

Segment SR
S (1, −1) and R (4, 0)
d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10
m equals 0 plus 1 over 4 minus 1 equals one third

Segment PS
P (0, 1) and S (1, −1)
d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1


Segment QR
Q (3, 2) and R (4, 0)
d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5
m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel. Segments PS and SR are perpendicular. Segments PQ and QR are perpendicular.
Russell
Jamie
Both
Neither
Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0

Jamie

Step-by-step explanation:

dybincka [34]3 years ago
3 0

Answer: Jamie

Step-by-step explanation:

Bcuz I took the test and made sure it was Jamie

You might be interested in
Http://prntscr.com/irtaxh<br> need help with this question
galben [10]
P will be the transversal if ∠10 and ∠14 are alternate interior.<span />
3 0
4 years ago
Solve for x:<br> 600<br> x + 124<br> Just enter the number.
Kryger [21]
Answer: -4. Reasoning: We are trying to get the angle of both lines to equal 180. If you add 60+124 together to see how much we have currently, your answer comes up to 184. That’s 4 over what we need, therefore, -4 would be needed to bring the current amount back down to 180.
3 0
3 years ago
I need help with this one too!
Gnoma [55]

Answer:

rectangle and quadrilateral

Step-by-step explanation:

7 0
3 years ago
Find the area of the region bounded by the $y$-axis, the line $y=6$, and the line $y = \frac{1}{2}x$.
Iteru [2.4K]

For a better understanding of the solution provided here please go through the diagram in the file that has been attached.

As can be clearly seen from the question and the graph, the area is bounded by a straight line y=\frac{1}{2}x which passes through the origin, the y axis and the horizontal line y=6.

As we can see from the graph, this is a right triangle. To find the point of intersection of the horizontal line y=6 and the line y=\frac{x\1}{2}x, we will have to equate the two as:

\frac{1}{2}x=6

Therefore, x=12

Thus, y=\frac{1}{2}x= \frac{1}{2}\times 12=6

Hence the point of intersection is (12,6) which is depicted on the graph too.

As this is a case of a simple right triangle, the area of the bounded region will thus be:

Area=\frac{1}{2}\times base\times height

Let the base be the y=6 line whose length is 12 and let height be the y axis whose length is 6, thus, the area will be:

Area=\frac{1}{2}\times 6\times 12=36 squared units.


7 0
3 years ago
2(x - 5) = 9 -3x + 6 + 8 + 3x + 7 X=?
Marianna [84]
2x-10= 28
+10 +10
2x= 28
x=14
7 0
3 years ago
Other questions:
  • What is the mass of a cow in metric units?
    9·1 answer
  • A triangle has side lengths of 15, 20, and 25. What type of triangle is it?
    7·2 answers
  • Which is the area of rectangle abcd
    7·1 answer
  • Find the range of f(x) = -x+4 for the domain {-3, -2, -1, 1}.
    12·1 answer
  • 128 divided by n = $8
    14·2 answers
  • Which answer choice shows 2.115 rounded to the nearest tenth?
    9·1 answer
  • Choose the correct classification of 2x+10^2-x^3
    10·2 answers
  • C+8+-20<br> c=<br><br> it made me write 20 characters
    8·1 answer
  • What is the domain of the following set of ordered pairs? {(7,1),(5,-4), (-3,3), (-6,-9)}​
    15·1 answer
  • Find the slope of the line that passes through the points A (3, -1), B (3,5) *
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!