Answer:
4, 6, 1
Step-by-step explanation:
We can solve this problem using a system of equations:
1) a + b + c = 11
2) 2a + 5b + 6c = 44
3) 4a - b = 10
First, we can substitute the value of b from equation #3 into equation #1:
b = 4a - 10
a + (4a - 10) + c = 11
5a - 10 + c = 11
5a + c = 21
c = 21 - 5a
Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:
2a + 5(4a - 10) + 6(21 - 5a) = 44
2a + 20a - 50 + 126 - 30a = 44
-8a + 76 = 44
-8a = -32
a = 4
b = 4a - 10 = 4(4) - 10 = 6
c = 21 - 5a = 21 - 5(4) = 1
<span>3m^-2 3n^3
--------- = -----------
5n^-3 5m^2
hope it helps</span>
Answer:
Step-by-step explanation:
Let t represent the time it took Emanuel to drive home from college. If the total round trip took 11 hours, it means that the time it took
Emanuel to drive from home back to college would be (11 - t) hours.
Emanuel drove home from college traveling an average speed of 70 mph.
Distance = speed × time
Distance covered by driving from college to home is
70 × t = 70t
He drove back to the college the following week at an average speed of 62.7 mph.
Distance covered by driving back to college from home is
62.7(11 - t) = 689.7 - 62.7t
Since the distance travelled is the same, then
689.7 - 62.7t = 70t
70t + 62.7 = 689.7
132.7t = 689.7
t = 689.7/132.7
t = 5.19 hours.
Therefore, the time that it took Emanuel to drive from home back to college is
11 - 5.19 = 5.81 hours
Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The other parameters are given as follows:

Hence, the lower bound of the interval is:

The lower limit of the 95% confidence interval is of $99,002.
More can be learned about the z-distribution at brainly.com/question/25890103
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