Question

A rock dropped on the moon will increase its speed from 0 m/s to 4.9 m/s in about 3 seconds. What is the acceleration of the rock

Answer 1

Answer:

Acceleration of the rock is 1.64 m/s²    

Explanation:

It is given that,

Initial speed of the rock, u = 0

Final speed of the rock, v = 4.9 m/s

Time taken by a rock, t = 3 seconds

We have to determine the acceleration of the rock. The acceleration of the rock is equal to the rate of change of velocity. Mathematically, it can be written as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{4.9\ m/s-0}{3\ s}$

$a=1.633\ m/s^2$

$a=1.64\ m/s^2$

So, the acceleration of the rock is 1.64 m/s². Hence, this is the required solution.

Answer 2

A = change in v/t
= vf - vi / t
= 4.9 - 0 / 3
= 1.6 m/s^2