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Mumz [18]
4 years ago
13

What is the solution to the system of equations y = -x - 5 and y = 2x + 4

Mathematics
1 answer:
Delvig [45]4 years ago
4 0

Answer:

(-3,-2)

Step-by-step explanation:

y = -x - 5

y = 2x + 4

plug in one of the y equations

(2x+4)= -x - 5

2x+4=-x-5

3x=-9

x= -3

plug in x to one of the y equations

y= -(-3) -5

y=3-5

y= -2

x= -3, y= -2

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3 years ago
Slove algebraically<br><br>3x - 4y = -24<br>x +4y=8<br>​
Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

<u>Solution:</u>

We have been given two equations which are as follows:

3x - 4y = -24   ----- eqn 1

x + 4y = 8   -------- eqn 2              

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

x = 8 - 4y  ------eqn 3

Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

24 - 12y - 4y = -24

-16y = -48

y = 3

Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

x = 8 - 4(3)

x = 8 - 12  = -4

Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

5 0
3 years ago
Find two consecutive odd integers whose product is 1443
liberstina [14]

Let's x represents the first odd integer

The next consecutive integer would be represented as x+2.

So x and x+2 being multiplied together will give us 1443:

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x^2+2x-1443=0

By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.

Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.

With that said you 1st pair will be: 37,39

Your second pair will be: -37,-39.



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Answer:

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Step-by-step explanation:

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3 years ago
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dlinn [17]
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