Given that Audra was drawing a perpendicular bisector of segment AB with a compass. She started with line segment AB. Then, she placed her compass point on A and opened the compass more halfway to B.
Her next step will be "Using the width of the compass from the previous step, draw two arcs to the left and right of both A and B".
Answer:
The scores in order from least likely to most likely is 8, 3, 4, and 5.
Step-by-step explanation:
1. Calculate the probability of the spinner adding up to 1, 2, 3, 4, .... 8
You will get:
2 (1/16)
3 (2/16)
4 (3/16)
5 (4/16)
6 (3/16)
7 (2/16)
8 (1/16)
2. Given the scores from the problem, the probability of each number is 3 (2/16), 4 (3/16), 5 (4/16), and 8 (1/16).
3. With this, we can determine the scores in order from least likely to most likely is 8, 3, 4, and 5.
Answer:
I bet you're smarter than me so you can figure it out
Step-by-step explanation:
good thing you aint like me
Answer:
Step-by-step explanation:
The concept of variance in random variable is applied in solving for the value of c for the estimator cW1 + (1 − c)W2 to be most efficient. Appropriate differentiation of the estimator with respect to c will give the value of c when the result is at minimum.
The detailed analysis and step by step approach is as shown in the attachment.
The required value is 
Step-by-step explanation:
Weight of ants = 
Weight of elephant= 
We need to find, the total weight of about how many ants equals to the weight of an oversized elephant.
The equation given is:

We need to find a:
Solving:

So, the required value is 
Keywords: Scientific Notation
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