Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
2. ΔABC is isosceles
Step-by-step explanation:
Given : m∠A = 50
m∠BCD = 180 - (m∠BDC + m∠DBC)
= 180 - (100 + 30)
= 50
then
m∠A = m∠BCD
therefore ΔABC is isosceles
Answer:
1,000 + 50= 1,050
400 + 15= 430
15 x 2 = 30
Their bill would be 1,050 + 430= 11480
Step-by-step explanation: