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hram777 [196]
3 years ago
14

A forest ranger sights a fire directly to the south. A second​ ranger, 7 miles east of the first​ ranger, also sights the fire.

The bearing from the second ranger to the fire is Upper S 22 degrees Upper W. How far is the first ranger from the​ fire?

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

17 miles

Step-by-step explanation:

Let the first Ranger be at A and the second Ranger at Point B.

Using alternate angles, ∠AXB=22°.

We want to determine the distance of the first ranger at point A to the fire(X).

Using trigonometry,

Tan = Opposite/Adjacent

Tan 22°= 7/|AX|

|AX| X Tan 22°= 7

|AX| = 7/Tan 22°=17.32560797391

= 17 miles( to the nearest mile)

The first ranger is 17 miles from the fire.

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Answer:

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that n = 1012, \pi = \frac{374}{1012} = 0.3696

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}

E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}

\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0
3 years ago
Please help please help please help you
tatyana61 [14]
40 students prefer vanilla. To get this answer you need to multiply 200 times 0.2 because you are trying to find 20%
4 0
2 years ago
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John can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. How long does it take for both John and Rocky to
mario62 [17]

Answer: it will take them 48 minutes.

Step-by-step explanation:

John can mow a lawn in 80 minutes. This means that the rate at which he moans the lawn per minute is 1/80

Rocky can mow the same lawn in 120 minutes. This means that the rate at which Rocky can mow the same lawn per minute is 1/120

If they work together, they would work simultaneously and their individual rates are additive. This means that their combined working rate would be

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Assuming it takes t hours for both of them to clean the room working together, the working rate per hour would be 1/t. Therefore,

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4 0
2 years ago
A cubical reservoir has capacity of 480000 l itters of liquid. If ifs length and breadth are 10m and 8m respectively, find the h
sertanlavr [38]

Answer:

Height = 6000 m

Step-by-step explanation:

Volume = length \times breadth \times height \\\\480000 = 10 \times 8 \times  height\\\\480000 = 80 \times height\\\\height = \frac{480000}{80} =  6000 \ m

5 0
3 years ago
300 30 3 0.3 follows what pattern
labwork [276]
Divide 10 each time.

300/10=30
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etc.
3 0
3 years ago
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