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hram777 [196]
3 years ago
14

A forest ranger sights a fire directly to the south. A second​ ranger, 7 miles east of the first​ ranger, also sights the fire.

The bearing from the second ranger to the fire is Upper S 22 degrees Upper W. How far is the first ranger from the​ fire?

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

17 miles

Step-by-step explanation:

Let the first Ranger be at A and the second Ranger at Point B.

Using alternate angles, ∠AXB=22°.

We want to determine the distance of the first ranger at point A to the fire(X).

Using trigonometry,

Tan = Opposite/Adjacent

Tan 22°= 7/|AX|

|AX| X Tan 22°= 7

|AX| = 7/Tan 22°=17.32560797391

= 17 miles( to the nearest mile)

The first ranger is 17 miles from the fire.

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32 33-cent stamps, 8 23-cent stamps

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In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

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To make our first equation, let's think about the number of stamps total we have. We can say:

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x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

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x+y=40\\x+8=40\\x=32

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