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Mathematics

1 answer:

valina [46]3 years ago

6 0

Have to multiply 3 times here. Let's begin by mult (2x^4)/(y^4) by (3x^3y)/(zy^3):

3*2 = 6

y/y^3 = 1/y^2

x^3*x*4 = x^7

z*y^3*y^4 = z*y^7

So, the product is

3x^7*y 3x^7
----------- and this can be reduced once more: ----------- (answer)
z*y^7 z*y^6

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Find the formula for the nth term of the arithmetic sequence -39, 61, 161, 261, ...

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<h3>Given that it is arithmetic</h3>

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In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability

Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by $P(Z>\frac{(25-27)}{3.29})$

What is the probability of success of a single trial of this experiment?

Options:

0.07
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0.79
0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

$\mu =\frac{np}{\sigma}$ = $\sqrt{np(1-p)}$