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Ratling [72]
2 years ago
10

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
6 0
Area would be 324 since it says S equals 3 cm and the formula is Area=6s^2 so I'd be 6 times 3 to the power of 2
Anon25 [30]2 years ago
5 0
First plug in s which is 3

So you get A=6(3^2)

WHAT IS 3^2   (3*3=9)
A=6(9)
A=54cm^2

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How many hundred thousands, ten thousands, and thousands are in 801,163
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3 years ago
Given that MQL =180° and XQR = 180°, which equation could be used to solve problems involving the relationships
Ganezh [65]

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2 years ago
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3 0
2 years ago
Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr
Degger [83]

Answer:

A=73.8\°

B=8.2\°

c=76.3\ units

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)

substitute the given values

c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)

c^{2}=5,823.5738

c=76.3\ units

step 2

Find the measure of angle A

Applying the law of sine

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}

sin(A)=(74)sin(98\°)/76.3

A=arcsin((74)sin(98\°)/76.3)

A=73.8\°

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

73.8\°+B+98\°=180\°

171.8\°+B=180\°

B=180\°-171.8\°=8.2\°

5 0
3 years ago
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