Answer:
0.03259..
Step-by-step explanation:
Answer:mn jjjjjjjjjjjjjjjjjjjjjjjj,uyhhhbgfvStep-by-step explanation:
Omg, im so sorry, i was moving and put my books on top of my keyboard it did this. Sorry. SOMEBODY DELETE THIS PLEASE. Sorry again.
Answer:
m<FAB = 75°
m<BAC = 105°
Step-by-step explanation:
First, find the value of x.
(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)
Solve for x
13x - 3 = 3x + 2 + 55
13x - 3 = 3x + 57
Collect like terms
13x - 3x = 57 + 3
10x = 60
Divide both sides by 10
x = 6
✔️m<FAB = 13x - 3
Plug in the value of x
m<FAB = 13(6) - 3 = 78 - 3
m<FAB = 75°
✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)
m<BAC = 180 - 75 (substitution)
m<BAC = 105°
Answer:
a) 0.5 = 50% of flanges exceed 1 millimeter.
b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
This means that 
(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

0.5 = 50% of flanges exceed 1 millimeter.
(b) What thickness is exceeded by 90% of the flanges?
This is x for which:

So




A thickness of 0.96 millimeters is exceeded by 90% of the flanges