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2 years ago

I hope u can help me

Mathematics

2 answers:

loris [4]2 years ago

8 0

Answer:

it's 831.74

Step-by-step explanation:

enot [183]2 years ago

3 0

Answer:

A≈6163.05

Step-by-step explanation:

the formula is A=2πrh+2πr2

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Based on the results of the simulation, if 224 groups are formed, about how many of them would you expect to contain one student

trapecia [35]

Answer: what's the results of the stimulation?, there's not much info to answer your question.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

1 year ago

Read 2 more answers

a pile of sand has a weight of 90kg The sand is put into a small bag, a medium bag and a large bag in the ratio of 2 : 3 : 7 Wor

just olya [345]

Hi there!

To split 90 kilos in the ratio of 2 : 3 : 7 we must first realise that we have a total of 2 + 3 + 7 = 12 parts, in which we must split the total 90 kilos.

12 parts equal 90 kilo, and therefore
1 part equals 90 / 12 = 7.5 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
2 parts equal 7.5 × 2 = 15 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
3 parts equal 7.5 × 3 = 22.5 kilos.

1 part equals 90 / 12 = 7.5 kilos, and therefore
7 parts equal 7.5 × 7 = 52.5 kilos.

Hence, 90 kilos in the ratio of 2 : 3 : 7
gives 15 kg, 22.5 kg and 52.5 kg.

~ Hope this helps you!

3 0

3 years ago

Plz help you have to find the angle marked x in each of these polygons

svetoff [14.1K]

Https://us-static.z-dn.net/files/dd0/5d5ddccb833d70732c67b84ec119f42f.jpeg