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4 years ago

8

The sum of 3 integers is 56. if one of the integers is the square root of 625, and the second is twice the square root of 81 , t

hen which prime number must be the third integer?

1 answer:

ira [324]4 years ago

8 0

A+b+c=56
a=√625=25
b=2√81 = 2x9=18
c = 56-25-18=13

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Answer:

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3 years ago

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3 years ago

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We can try to factorize all the options one by one.

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