Which equation involves a prime quadratic and cannot be solved by factoring? A. x2 + 5x − 4 = 0 B. x2 − x − 6 = 0 C. x2 + 3x − 4
1 answer:
Answer:
Option A
Step-by-step explanation:
We can try to factorize all the options one by one.
For A:
We can see that the quadratic expression cannot be solved by factorization as the factors at the end of factorization are not equal in both brackets. So Option A is the correct answer for the given question.
Moreover we can also note that all the other quadratic expressions can be factorized ..
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He product of two positive numbers is 750. The first number is 5 less than the second number. The equation x(x – 5) = 750 can be used to find x, the value of the greater number. What is the value of the greater number?
Solution
Here the second number is "x"
The first number is "x - 5"
The equation is x (x - 5) = 750
- 5x = 750
Subtract 750 from both sides, we get
Solving the above quadratic equation using quadratic formula, we get
Here we have to plug in a =1, b = -5 and c = -750 in the above formula, we get
When we simplify the above expression is...
x = 30 and x = -25
x = -25 cannot be the solution since it is negative value.
x = 30 is the solution.
Here "x" represents the second number which is 30, that is the greater number.
Therefore, the answer is 30.