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3 years ago

How to write 438 in standard

Mathematics

2 answers:

Anton [14]3 years ago

8 0

400+30+8 is how you put 438 in standard form.

Naily [24]3 years ago

4 0

Four Hundred, Thirty, Eight. [To Write Numbers In Standard For You Need To Break Them Down Into Groups. For Example, For The Number 123 You Would Break It down To Where It Looks Like This (100+20+3). Then You Write It In Letter Form (One Hundred, Twenty, Three).]

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Ashirt button has a diameter of 0.61 cm. Which of these is an approximate measurement of the circumference of the button?

Aleonysh [2.5K]

Answer:

1.92cm

Step-by-step explanation:

Circumference of a circle is computed using the formula:

$C=2\pi r$

Where:

r = radius

π = 3.14

Since the radius is the distance of the center of the circle from any point of the circle and the diameter is the measure of a straight line that goes across the center of the circle from one side to the other, radius is half of a diameter. So the diameter = 2r.

We can then use the diameter to solve for the circumference by using the formula"

$C = \pi d$

So we just plug in what we know in the formula:

$C = \pi d\\\\C = (3.14)(0.61cm)\\\\C = 1.9154cm\cong1.92cm$

3 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

jonny [76]

Answer:

Step-by-step explanation:

1) ∠1 + 33 = 180 {Straight line}

∠1 = 180 - 33

∠1 = 147

2){Exterior angle of a triangle equals the sum of opposite interior angles}

∠2 = 47 + 33

∠2 = 80

3) ∠2 +x = 180 {straight line}

80 + x = 180

x = 180 - 80

x = 100

{Exterior angle of a triangle equals the sum of opposite interior angles}

∠3 = 100 + 48

∠3 = 148

8 0

3 years ago

Read 2 more answers

A system of equations is shown:

Harrizon [31]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x=-y+6&(1)\\-4x+3y=8&(2)\end{array}\right\\\\(1)\\-y+6=2x\qquad\text{subtract 6 from both sides}\\-y=2x-6\qquad\text{change the signs}\\y=6-2x\\\\\text{substitute it to (2):}\\\\(2)\\-4x+3(6-2x)=8\qquad\text{use the distributive property}\\-4x+(3)(6)+(3)(-2x)=8\\-4x+18-6x=8\qquad\text{subtract 18 from both sides}\\-10x=-10\qquad\text{divide both sides by (-10)}\\x=1\\\\\text{put the value of x to (1):}\\\\y=6-2(1)\\y=6-2\\y=4$