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avanturin [10]
3 years ago
9

a wheelchair ramp is in the shape of a triangular prism it has a base area of 37.4 square yards and a height of 5 yards find the

volume of the ramp.
Mathematics
1 answer:
Eva8 [605]3 years ago
6 0

Answer:

The volume of the ramp is 187\ yd^{3}

Step-by-step explanation:

we know that

The volume of the triangular prism (ramp) is equal to

V=BH

where

B is the area of the triangular base of the prism

H is the height of the prism

we have

B=37.4\ yd^{2}

H=5\ yd

substitute the values

V=37.4(5)=187\ yd^{3}

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pav-90 [236]
16 pi which is 3.14 so 16x3.14
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3 years ago
The half price of helium-5 is 7.6 X 10 to the power of negative 22 seconds and the half-life helium -9 is 7 x 10 to the power of
Digiron [165]

Answer:

Approximately 9.211 times

Step-by-step explanation:

Given

x = 7.6 * 10^{-22}s --- half life of helium-5

y = 7 * 10^{-21}s --- half life of helium-9

Required

How many times greater is y than x

To do this, we simply divide y by x

\frac{y}{x} = \frac{7 * 10^{-21}s}{7.6 * 10^{-22}s}

\frac{y}{x} = \frac{7 * 10^{-21}}{7.6 * 10^{-22}}

Apply law of indices

\frac{y}{x} = \frac{7 * 10^{-21--22}}{7.6}

\frac{y}{x} = \frac{7 * 10^{-21+22}}{7.6}

\frac{y}{x} = \frac{7 * 10}{7.6}

\frac{y}{x} = \frac{70}{7.6}

\frac{y}{x} = 9.211

5 0
3 years ago
Identify the zeros of the function f(x) = 2x^2 − 4x + 5 using the Quadratic Formula
Nostrana [21]

For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.

Then, we must find the roots of:

2x ^ 2-4x + 5 = 0

Where:

a = 2\\b = -4\\c = 5

We have to:x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Substituting we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (2) (5)}} {2 (2)}\\x = \frac {4 \pm \sqrt {16-40}} {4}\\x = \frac {4 \pm \sqrt {-24}} {4}

By definition we have to:

i ^ 2 = -1

So:

x = \frac {4 \pm \sqrt {24i ^ 2}} {4}\\x = \frac {4 \pm i \sqrt {24}} {4}\\x = \frac {4 \pm i \sqrt {2 ^ 2 * 6}} {4}\\x = \frac {4 \pm 2i \sqrt {6}} {4}\\x = \frac {2 \pm i \sqrt {6}} {2}

Thus, we have two roots:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

Answer:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

3 0
4 years ago
Subtract 9 from 15 then multiply by 5
nlexa [21]
(15-9)*5= 30
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5 0
3 years ago
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The value of 21b - 32 + 7 b - 20 b is​
Aleonysh [2.5K]
8b - 32

Hope it’s right
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3 years ago
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