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Cloud [144]
3 years ago
5

I need help answering this math question.

Mathematics
1 answer:
alexdok [17]3 years ago
5 0
The answer is C . you have to solve it like that

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the art club receives $10 plus $2 for every sculpture they sell for a fundraiser. the expression 2x+10 represents the amount the
Len [333]
2x + 10...the common number between these 2 terms is 2...so factor the 2 out

2(x + 5) <==
8 0
3 years ago
Sabeena had 15 3/4m long ribbon. She cut into two pieces such that the length of one pieces is 9 1/2m. Find the length of other
DochEvi [55]

Answer:

6 1/4

Step-by-step explanation:

Total length of the ribbon= 15 3/4 m= 63/4 m

One piece= 9 1/2 m= 19/2 m

Other piece length =X

X= 63/4-19/2

  =63/4-38/4

  =25/4

  =6 1/4

3 0
3 years ago
Read 2 more answers
Which of the following is the solution of the following inequality?
Brums [2.3K]

Answer:

x = 3

Step-by-step explanation:

4 + 12.5 > 11x - 3.5 - 2x

16.5 = 5.5x

16.5/5.5 = x

5 0
3 years ago
What is the numerical coefficient of this term -3z
denpristay [2]
The numerical coefficient of this term is -3.
3 0
3 years ago
If p is a polynomial show that lim x→ap(x)=p(a
Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

 

Solution. Notice that

 

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

 

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

 

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

 

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

 

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0
3 years ago
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